Tentukan hasil himpunan penyelesaian nilai mutlak berikut ini!

|2x/3+4|=1/7
|2x+12|=3/7
(2x+12)2=(3/7)2
4x2+48x+144=9/49
4x2+48x+144-9/49=0
4x2+48x+143 40/49=0
a=4
b=48
c=143 40/49
RUMUS ABC => x1,2 = { -b ± √(b 2 - 4ac) } / 2a
x1,2 = (-48± √(48x48-4x4x143 40/49))/2x4
x1= -81/14
x2=-87/14