persamaan bayangan garis 2x+3y+1=0 karena refleksi terhadap sumbu y dilanjutkan rotasi pusat O sebesar phi/2 adalah.... tolong yahh

Transformasi

T1 (R sb y) dilanjutkan T2 {R(O, 1/2 π)

T2 o T1 = [0..-1||1...0|. |-1..0||0...1| = |0...-1||1...0|
(x',y') = (0..-1||1..0)(x,y) = (-y, x)
x' = -y --> y = -x'
y' = x ---> x = y'

2x+3y +1 = 0 ---> 2(y') + 3(-x') + 1 = 0
2y - 3x +1= 0
atau
3x - 2y - 1 = 0