Diketahui suku banyak f(x)=2x³-3x²+3x-2 . Nilai 3f(4)-2+(2) ...

[tex]f(4)=2(4^{3})-3(4^{2})+3(4)-2 \\ f(4)=2(64)-3(16)+12-2 \\ f(4)=128-48+10 \\ f(4)=90 \\ \\ 3f(4)-2+2=3f(4)=3(90)=270 [/tex]