x-2/x+2=x-4/x+4 hasilnya brp??

[tex] \frac{x-2}{x+2}= \frac{x-4}{x+4}\\ (x-2)\times(x+4) = (x+2) \times(x-4)\\ x^2+2x-8=x^2-2x-8\\ x^2-x^2+2x+2x=-8+8\\ 0+4x=0\\ 4x=0\\ x=0\div4\\ \bold{x=0}[/tex]