Hitunglah tekanan uap larutan NaOH 10% jika diketahui tekanan uap air adalah 10,5 mmHg

diket : NAOH = 10% = 10 gr
AIR = 90% = 90 gr
NAOH --> ( 23 + 16 + 1 = 40 )
H2O --> ( 1 + 1 + 16 )
nt = gr/Mr = 10/40 = 0,25 mol
np = gr/Mr = 90/18 = 5 mol
P = Xt × P°
= (nt ÷ (nt + np)) × P°
= (0,25 ÷ (0,25 + 5)) × 10,5
= (0,25 ÷ ( 5,25 )) × 10,5

= 0,525 Mmhg maaf kalau salah