2x + 10y = 6 -3x - 5y = 1 Selesai kan dengan cara substitusi

2x+10y=6
2x = 6 -10y
x = 3-5y

-3x-5y = 1
-3 (3-5y) - 5y = 1
-9 + 15y - 5y = 1
10y = 10
y = 1

x = 3 - 5y
x = 3 - 5(1)
x = 3 - 5
x = -2

2x + 10y = 6 ⇒ x = (6 - 10y)/2 ... (1)

-3x - 5y = 1 ... (2)

⇒Substitusi (1) ke (2)
-3[(6 - 10y)/2] - 5y = 1
(-18 + 30y)/2 - 5y = 1
-18 + 30y - 10y = 2
20y = 20
y = 1

⇒Substitusi y = 1 ke (1)
x = [6 - 10(1)]/2
x = -4/2
x =  -2