pertidaksamaan kuadrat dengan cara rumus 2x^(2)+6x-8=0

Cara pemfaktoran
2x^2 + 6x - 8 = 0 =====> bagi 2
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x = -4 atau x = 1

Cara Rumus ABC
2x^2 + 6x - 8 = 0
a = 2, b = 6, c = -8
x = (-b ± √(b^2 - 4ac)) / 2a
= (-6 ± √(6^2 - 4(2)(-8)) / 2(2)
= (-6 ± √(36 + 64)) / 4
= (-6 ± √100) / 4
= (-6 ± 10)/4
x = (-6 + 10)/4 = 4/4 = 1
atau
x = (-6 - 10)/4 = -16/4 = -4

2x² + 6x - 8 = 0
x² + 3x - 4 = 0
(x + 4) (x - 1) = 0
x = -4
x = 1