Tentukan nilai dari 2log80+2logakar16+2logakar1/32-2log5=

2log80 + 2log[tex] \sqrt{16} [/tex] + 2log[tex] \sqrt{ \frac{1}{32} } [/tex] - 2log5
=> 2log( 80 x [tex] \sqrt{16} [/tex] x [tex] \sqrt{ \frac{1}{32} } [/tex] : 5 )
=>2log( 80 x 4 x [tex] \frac{1}{ 2^{ \frac{5}{2} } } [/tex] :5 )
=> 2log ( 16 x 4 x [tex] 2^{-\frac{5}{2} } [/tex] )
=> 2log ( [tex] 2^{4} x 2^{2} x 2^{ -\frac{5}{2} } )[/tex]
=> 2log[tex] 2^{ \frac{7}{2} } [/tex]
=> [tex] \frac{7}{2} [/tex]

kalo ga salah ya jawabannya