ada yg bisa tolong gak?... soalnya aku gak engerti sama sekali.... tolong dibantu ya^_^

[tex]16 ^{x+3} = \sqrt[4]{64 ^{x+4} } \\ (4 ^{2}) ^{x+3}=(4 ^{3}) ^{ \frac{x+4}{4} } \\ 2x+6= \frac{3x+12}{4} \\ 8x+24=3x+12 \\ 5x=-12 \\ x=-2,4 [/tex]