tolong dong plisss..

^ pangkat
5) h'(x) = (2x + 7)²
h'(x) = (2)(2)(2x + 7)
h'(x) = 4(2x+7)
h'(x) = 8x + 28

6) l(x) = 2(3x² -7x + 1)³
l'(x) = 2(3)(6x-7)(3x² - 7x + 1)²
= (36x - 42)(3x² - 7x + 1)²

7) h(x) = (5x+7)² / (2x+1)
h'(x) = {(50x+70)(2x+1) - 2(5x+7)²} / (2x+1)²
= (100x²+190x+70-50x²-70x-98) / (2x+1)²
= (50x² + 120x - 28) / (2x-1)²