Matematika

Pertanyaan

(1 per 3)³×( 1per 5)²× (30⁴) per 16²=

2 Jawaban

  • Hasil dari ( 1 per 3)pangkat 3 * (1 per 5) pangkat 2 *(30pangkat 4) per 16 kuadrat = 75 per 16.
  • (1/3)^3 × (1/5)^2 × (30^4)/16^2
    = (1/3)^3 × (1/5)^2 × (2^4 × 3^4 × 5^4)/(2^4)^2
    = 3^-3 × 5^-2 × (2^4 × 3^4 × 5^4)/2^8
    = (3^-3 × 3^4) × (5^-2 × 5^4) × (2^4 × 2^-8)
    = 3^1 × 5^2 × 2^-4
    = 3^1 × 5^2 × (1/2^4)
    = 3 × 25/16
    = 75/16
    = 4 11/16

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