tolong dibantu ya... saya masih kurang paham :(

f(m,b) = 1000m + 3000b

m + b ≤ 24
10m + 20b ≤ 300 |÷10| m + 2b ≤ 30
eliminasi
m + b = 24
m + 2b = 30
------------------ _
-b = -6
b = 6
m + b = 24
m + 6 = 24
m = 24-6 = 18
titik (m,b) ada 3 titik 1(24,0) 2(18,6) 3(0,15)
f(24,0) = 1000(24) + 3000(0) = 24.000
f(18,6) = 1000(18) + 3000(6)
= 18.000 + 18.000
= 36.000
f(0,15) = 1000(0) + 3000(15) = 45.000
hasil maks 45.000