Mohon bantuannya so mtk no.3

vkerucut=1/3x3,14x12x12x12
=3,14x4x12x12
=1808,64
v tabung=3,14x12x12x3
=1256,48
v=1808,64-1256,48= 552,16 cm^3

jari2 kerucut1 12
jari2 kerucut2 3
jari2 alas tabung 3
tinggi tabung 12

volume kerucut kepancung
vol.kerucut1 - vol. tabung - vol.kerucut2

disini kita blom tau tinggi kerucut itu berapa, tapi kita bisa nyari pake prinsip kesebangunan
ket.
rk1 = jari2 kerucut1
rk2 = jari2 kerucut2
tt = tinggi tabung
tk2 = tinggi kerucut2

"rk1 / tt+tk2 = rk2/tk2"
tk2 = rk2 (tt+tk2) /rk1
tk2 = 3(12+tk2) / 12
tk2 = 36 + 3tk2 /12
12tk2 = 36 + 3tk2
9tk2 = 36
tk2 =4

inget juga
tk1 = tt+tk2
tk1 = 12+4
tk1= 16

udah deh tinggal masukin rumus
v.k1- v.k2 -v.t
(tr^2 - tr^2)π/3 - tπr^2
((16.12.12)-(4.3.3))π/3 - (12.3.3.π)
(2304-36)π/3 -108π
2268π/3 - 108π
756π - 108π
648π
2036,57... cm^3
maap jawabnya kurang jelas, soalnya lambang2 di keyboardnya terbatas.-.