tolong sama caranya ya integral -4 3akar x dx

^ tanda pangkat
-4 ³√x dx
= -4(x)^⅓ dx
= (-4 / 1+⅓) x^(1+⅓) + C
= (-4 / 4/3) x^4/3 + C
= (-4 × 3/4) x^4/3 + C
= -3x^4/3 + C
= -3x(³√x) + C