tolong bantu yaaaa . nyari ga ketemu2 jawabannya-_-

int x(x+4)^5  dx
misal, u = x + 4 -----> x = u - 4
du = dx

integral di atas dapat menjadi :
= int (u - 4)u^5 du
= int (u^6 - 4u^5) du
= 1/7 u^7 - 2/3 u^6 + C
= u^6 (1/7 u - 2/3) + C
= u^6 (3/21 u - 14/21) + C
= u^6 (3u - 14)/21 + C
= 1/21 (3u - 14) u^6 + C
substitusi, u = x + 4,
= 1/21 (3(x+4) - 14)(x+4)^6 + C
= 1/21 (3x-2)(x+4)^6 + C

JAWABAN : E