∫ 2 batas atas 0 batas bawah (x+1)^2 dx

Penyelesaian:

[tex] \int\limits^2_0 {(x+1)^2} \, dx [/tex]
= [tex] \int\limits^2_0 {x^2+2x+1} \, dx [/tex]
= 1/3 x^3 + x^2 + x ] 0-2
= 1/3 (8) + 4 + 2
= (8 + 12 + 6) / 3 = 26/3