3(b²+b-a)-3a+b²= 6a-3b²+2c+2a-7c+2b²=
Matematika
fatih07hilmi
Pertanyaan
3(b²+b-a)-3a+b²=
6a-3b²+2c+2a-7c+2b²=
6a-3b²+2c+2a-7c+2b²=
1 Jawaban
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1. Jawaban minakhussaniah
3(b²+b-a)-3a+b² = 3b²+3b-3a-3a+b²
= -6a+4b²+3b
6a-3b²+2c+2a-7c+2b² = 6a+2a-3b²+2b²+2c-7c
= 8a-b²-5c