Sederhanakanlah! 1.a-(b-c)+a(b-c)+b-(c+a)= 2.a[a+{a-(b+a)}]= 3.a-[2a+{3b-(4c-2a)}]= 4.{a-(b-c)}-{b-(c-a)}-{c-(a-b)}=

1. a-(b-c)+a(b-c)+b-(c+a)
= a- b + c + ab - ac + b - c + a
= 2a + ab - ac
2. a[a+{a-(b+a)}]
= a [a + {a - b - a}]
= a [a + {-b}]
= a [a - b]
= a² - ab
3. a-[2a+{3b-(4c-2a)}]
= a - (2a+(3b-4c +2a))
= a- (2a +3b-4c+2a)
= a-4a-3b +4c
= -5a -3b +4c
4.{a-(b-c)}-{b-(c-a)}-{c-(a-b)}
= (a-b+c) -(b-c +a) - (c-a+b)
= a-b + c -b +c -a -c +a -b
= a -3b + c

mohon maaf klo ada kesalahan saya disini juga sambil belajar