larutan NaOH (mr = 40) 80% memiliki fraksi mol...

NaOH 80%

NaOH : Pelarut = 80:20


Dimisalkan:

NaOH = 80gram
Pelarut = 20gram (dianggar air)
Mr Air = 18

n NaOH = 80g/40 = 2 mol
n H20  =20g/18 = 10/9 mol

[tex]x_{NaOH} = \frac{2}{(2+ \frac{10}{9} )} \\ x_{NaOH} = \frac{18}{28} = 0.64[/tex]