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Pertanyaan

hitunglah molalitas dan fraksi mol larutan NaOH dalam air yg kadar nya 40% (Mr NaOH =40).

1 Jawaban

  • NaOH 40% dalam 100 gram larutan = 40 gram
    Massa air = 100 - 40 = 60 gram

    Molalitas = n . 1000/p
    = 40/40 gr/mol . 1000/60
    = 16,67 molal

    XNaOH = nNaOH / (nNaOH + n air)
    = (40/40) / ((40/40) + (60/18))
    = 1/(1+3,34)
    = 1/4,34
    = 0,23

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