Matematika

Pertanyaan

Di ketahui 3 log 2 = a dan 7 log 3 = b .maka nilai 3 log 28 =....

2 Jawaban

  • 3 log 28
    = 3 log 2² + 3 log 7
    = 2 3log2 + 3log 7
    = 2a + 1/b
  • [tex]^3log2=a ~~~~~~~^7log3=b \\ \\ ^3log28=~^3log4+~^3log7=~2~^3log2+ \frac{1}{^7log3} =2a+ \frac{1}{b} [/tex]

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