limit mat ipa part 15 jelaskan dgn caranya

>pembuktian
[tex] \lim_{n \to 0} \frac{4tan5x}{3x} = \frac{4tan5(0)}{3(0)}= \frac{0}{0} [/tex][bentuk tak tentu]

>penyelesaian
[tex]\lim_{n \to 0} \frac{4tan5x}{3x} =\lim_{n \to 0} \frac{4(5x)}{3x}=\lim_{n \to 0} \frac{4(5)}{3}= \frac{20}{3} [/tex]